36=18t-4t^2/2

Solution for 36=18t-4t^2/2 equation:

36=18t-4t^2/2

We move all terms to the left:

36-(18t-4t^2/2)=0

We get rid of parentheses

4t^2/2-18t+36=0

We multiply all the terms by the denominator


4t^2-18t*2+36*2=0

We add all the numbers together, and all the variables

4t^2-18t*2+72=0

Wy multiply elements

4t^2-36t+72=0

a = 4; b = -36; c = +72;
Δ = b2-4ac
Δ = -362-4·4·72
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12}{2*4}=\frac{24}{8}
=3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12}{2*4}=\frac{48}{8}
=6
$